SQL語句：select s.Name,C.Cname from student_course as sc left join student as s on s.Sno=sc.Sno left join course as c on c.Cno=sc.Cno
執行結果：
此條SQL執行的結果是學生選課的情況。
以下是特色補充：
select * from (SELECT id,jihao, ht.hetongid, hetonghao, banshichu, zulindanwei, jiansheluduan, shebeijinchangriqi,hetongfangshi, jine,yusuangongchengliang,(ht.jine/30)*(datediff(day,ht.shebeijinchangriqi,getdate())) as yusuanjine,yihuikuanjine, ((ht.jine/30)*(datediff(day,ht.shebeijinchangriqi,getdate()))-yihuikuanjine) as qiankuanjine,ht.shebeituichangriqi FROM db_hetongguanli_y_g as ht left join select sum (gongchengliang) as yusuangongchengliang ,hetongid from db_meirigongchengliang group by hetongid) as d on ht.hetongid=d.hetongid left join(select sum(shijihuikuanjine) as yihuikuanjine,hetongid from db_huikuan group by hetongid) as a on ht.hetongid=a.hetongid ) as b where b.hetongfangshi='月租' and b.hetongid=(select hetongid from db_shebeixinxi where jihao='" + this.DropDownList1.SelectedValue + "')";
select * from (select ht.id,ht.qiandingren,ht.hetongid,ht.banshichu,ht.jihao,ht.hetonghao,ht.zulindanwei, ht.jiansheluduan,ht.qingqianriqi,ht.lumianshigongcailiao,ht.hetongfangshi,ht.jine,ht.hetongqiandingriqi, ht.hetongjiesuanjine,ht.hetongjiesuanriqi,ht.shebeijinchangriqi,ht.shebeituichangriqi,ht.jiesuangongchengliang, d.yifukuanjine, (ht.hetongjiesuanjine-d.yifukuanjine) as qiankuanjine,ht.kaipiaojine,ht.ranyoufei,ht.yunfei, ht.qitafeiyong,ht.feiliaofei from db_hetongguanli_y_g as ht left join (select hetongid,sum(shijihuikuanjine) as yifukuanjine from db_huikuan group by hetongid) as d on ht.hetongid=d.hetongid) as a where a.hetongid=(select hetongid from db_shebeixinxi where jihao='5666') go
